Stanfield is a census-designated place (CDP) in Pinal County, Arizona, United States. The population was 651 at the 2000 census.
Stanfield is located at 32°52′54″N 111°57′49″W / 32.88167°N 111.96361°W / 32.88167; -111.96361 (32.881612, -111.963473).
According to the United States Census Bureau, the CDP has a total area of 4.0 square miles (10 km), all of it land.
As of the census of 2000, there were 651 people, 187 households, and 146 families residing in the CDP. The population density was 164.2 people per square mile (63.5/km²). There were 202 housing units at an average density of 51.0/sq mi (19.7/km²). The racial makeup of the CDP was 50.69% White, 3.99% Black or African American, 11.37% Native American, 0.92% Pacific Islander, 30.88% from other races, and 2.15% from two or more races. 61.60% of the population were Hispanic or Latino of any race.
There were 187 households out of which 37.4% had children under the age of 18 living with them, 44.9% were married couples living together, 23.5% had a female householder with no husband present, and 21.9% were non-families. 17.1% of all households were made up of individuals and 9.1% had someone living alone who was 65 years of age or older. The average household size was 3.48 and the average family size was 3.94.
In the CDP, the population was spread out with 32.6% under the age of 18, 11.8% from 18 to 24, 28.0% from 25 to 44, 17.7% from 45 to 64, and 10.0% who were 65 years of age or older. The median age was 28 years. For every 100 females, there were 101.5 males. For every 100 females age 18 and over, there were 100.5 males.
The median income for a household in the CDP was $22,391, and the median income for a family was $32,614. Males had a median income of $15,938 versus $15,000 for females. The per capita income for the CDP was $9,210. About 32.1% of families and 32.6% of the population were below the poverty line, including 51.9% of those under age 18 and 20.0% of people of age 65 or over.